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Unlimited Top Fuel (how quick & fast?)

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DaveRenk

Nitro Member
Anyone have a feel for how quick and/or fast would a 500 CID Top Fuel car using nitro run (1320 feet)? I'm talking no other restrictions (limiter, wing angle, etc.).

I have a feeling that the limiter does very little?
 
They've already been low .40's, so I don't see any reason to believe they couldn't run .30's by now. Traction is the problem, not the cars. If they turned 'em loose with traction control.........................whew!!!!

Sean D
 
What an opportunity to do some math!

I've heard a TF car can go from 0 to 100 mph in 0.8 seconds.

which equates to 0 to 147 ft / sec in 0.8 sec (183 ft per second squared)

-or- about 5.69 G's at the hit of the throttle (1G = 32.2 ft/sec^2)

lets assume you can maintain that for the full quarter (which they cant do just yet, but assume technology allows them to do that some day {we know the tires can handle it cause they are pulling that in the first .8 seconds today})

using the ol physics equation X = Xi +Vi T + 1/2 A T^2
X = 1320' (in this case)
Xi = 0' (initial position)
Vi = 0 (initial velocity)
T = time
A = acceleration (147 ft per second squared)

Solving for T we get a run in the quarter of 3.79 seconds

using the basic physics equation V = Vi T + 1/2 A T^2

knowing V = Velocity
Vi = 0 ft/sec Initial velocity
T = Time
A = Acceleration

Solving for V we get 1314 ft/sec

or about 896 miles per hour

So, if they could maintain 5.69G's through the entire run, theoretically they could have runs someday of:

3.79 seconds at 896 miles per hour.

Now if they can create a tire that can bond to the track better and not explode they could probably run faster.:D
 
What an opportunity to do some math!

I've heard a TF car can go from 0 to 100 mph in 0.8 seconds.

which equates to 0 to 147 ft / sec in 0.8 sec (183 ft per second squared)

-or- about 5.69 G's at the hit of the throttle (1G = 32.2 ft/sec^2)

lets assume you can maintain that for the full quarter (which they cant do just yet, but assume technology allows them to do that some day {we know the tires can handle it cause they are pulling that in the first .8 seconds today})

using the ol physics equation X = Xi +Vi T + 1/2 A T^2
X = 1320' (in this case)
Xi = 0' (initial position)
Vi = 0 (initial velocity)
T = time
A = acceleration (147 ft per second squared)

Solving for T we get a run in the quarter of 3.79 seconds

using the basic physics equation V = Vi T + 1/2 A T^2

knowing V = Velocity
Vi = 0 ft/sec Initial velocity
T = Time
A = Acceleration

Solving for V we get 1314 ft/sec

or about 896 miles per hour

So, if they could maintain 5.69G's through the entire run, theoretically they could have runs someday of:

3.79 seconds at 896 miles per hour.

Now if they can create a tire that can bond to the track better and not explode they could probably run faster.:D

Mods.... can we please have this guy banned!! :D :D
 
"A = acceleration (147 ft per second squared)"

I see a typo, I used 183 ft per second squared in the calcs, not 147

Come on now! Math is fun! (BTW I am an engineer in the real world)
 
"A = acceleration (147 ft per second squared)"

I see a typo, I used 183 ft per second squared in the calcs, not 147

Come on now! Math is fun! (BTW I am an engineer in the real world)

Aspirin please!!

I try to stay focused on what's after the =

How you get there makes my eyes cross..but the sum of it all is very cool.

Thanks Nick
 
well uh.... excuse me while i push my reading glasses up.... i do believe the correct formula is X=32(L7/M4)/68(U6-J6003)

J=Wind Velocity
U=Motor Displacement
M=Wing Angle
L= Horsepower

According to my calculations... my glasses keep falling down sorry, a top fuel can run .8348294755 seconds at 194,484 MPH hope this helps....
 
Cool thread. Without using all the math, simple comparisons tell me if a fuel car went from say a 4.42 et down to a 3.79 in the 1/4 mile, I don't see it picking up over 500MPH! Unless I misunderstood. Rocket cars have run in the 3's at somewhere over 400mph. 896 is well over Mach1!
 
The formula is much simplier

If a Cow and a half and a calf and a half can eat a bale of hay and a half in a day and a half, then a T/F car, without limitations can cross the 1320 foot mark before it leaves the starting line at faster than the speed of light... please see uncle Albert's E=MC2...

1.5C +1.5ca+1.5bh-36hr= -.0000000001
d'kid
 
Yeah, I forgot about the sound barrier thing. Plus the tires would probably blow apart at some point.

I don't really understand how though they can pull that 5.5+ G's at the start and then only run 4.50's at 330 though (as the math showed they should be running crazy times & speeds). Initally the 5G weight transfer glues the tires to the track (cause the wing isn't active yet with no wind), then as you accelerate less downtrack the wing takes over to hold the tires down. If you could hold the high rate of acceleration you wouldn't think you'd need the wing because the tires would be planted. But then theres probably stability issues.

Because the weight of the car is the same, it takes the same energy to accelerate the car no matter what the initial speed (meaning if it takes X energy to go from 0 to 100 in .8 seconds, they could go 100 to 200 in .8 seconds etc.) Maybe its wind resistance or something holding them back or making it harder to accelerate down track.
 
What an opportunity to do some math!

I've heard a TF car can go from 0 to 100 mph in 0.8 seconds.

which equates to 0 to 147 ft / sec in 0.8 sec (183 ft per second squared)

-or- about 5.69 G's at the hit of the throttle (1G = 32.2 ft/sec^2)

lets assume you can maintain that for the full quarter (which they cant do just yet, but assume technology allows them to do that some day {we know the tires can handle it cause they are pulling that in the first .8 seconds today})

using the ol physics equation X = Xi +Vi T + 1/2 A T^2
X = 1320' (in this case)
Xi = 0' (initial position)
Vi = 0 (initial velocity)
T = time
A = acceleration (147 ft per second squared)

Solving for T we get a run in the quarter of 3.79 seconds

using the basic physics equation V = Vi T + 1/2 A T^2

knowing V = Velocity
Vi = 0 ft/sec Initial velocity
T = Time
A = Acceleration

Solving for V we get 1314 ft/sec

or about 896 miles per hour

So, if they could maintain 5.69G's through the entire run, theoretically they could have runs someday of:

3.79 seconds at 896 miles per hour.

Now if they can create a tire that can bond to the track better and not explode they could probably run faster.:D

Uncle Jed, Uncle Jed, ...this man done got himself a sixth grade EDucation. :D
 
I hereby refer you to a hot-rodding mainstream magazine article from the late 80's/early 90's ... on Don Garlits' "NFR car"; ("No Foolish Rules") .....

Holy crap! It's interesting to think... with a lil' bit O' cash, plus probably a few risky investors, coupled with Don's logistical and technical mastery, what that conception could have potentially realized! It would make the folks at Bonneville feel and like experimental chimps!
 
I'm going to go way out on a limb here and predict you won't 896 mph from a top fuel car anytime soon.

...unless there are some rules changes.

(like 5 mile dragstrips)
 
fukitol-1.jpg
 
Yeah, I forgot about the sound barrier thing. Plus the tires would probably blow apart at some point.
Maybe its wind resistance or something holding them back or making it harder to accelerate down track.

Might be a little problem with getting the engine to rev! Assuming that the circumference of the tire (before it blows) is approximately 12 feet, tire will be rotating 109.5 times per second. 109.5 rev/sec x 60 sec/min x rear end ratio of 2.7 (I think that's right) = 17,739 rpm - :eek: Feel free to check my math - I'm a little rusty.

Also, I believe drag increases as the square of speed. Have no idea how to do that math, but it's gotta be a REALLY big number - :D
 
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